$x^{123}x^{123}\frac{x}{y}\beta\leq\leq\frac{x}{y}\lfloor x \rfloor\left[ \right]$
Zadania z matematyki
8 pkt - 14.12.2025 (13:05)
8 pkt - 9.11.2025 (18:27)
$x^{123}x^{123}\frac{x}{y}\beta\leq\leq\frac{x}{y}\lfloor x \rfloor\left[ \right]$