3  zadania. kto pierwszy?

1)
A) 1/64
B) 1/81
C)7 + (1/2)^-3 = 7 + 8 = 15 albo 7* (1/2)^-3= 7* 8 = 56, bo nie wiem czy brak mnożenia przy 7 oznaczał ułamek mieszany, czy zapomniałeś mnożenia
D)(2187/16384)^-1 = 16384/2187
E)2^(3+4-5) = 2^2 = 4
F) 5^(4-2-3) = 5^-1 = 1/5
G) 3^6 * 3^2 / 3^3 = 3^(6+2- 3 ) = 3^5 = 243
H) 6^4 * (6^2)^-1/ 6^-1 = 6^(4-2-(-1))= 6^ 3= 216

2) 
A) ((2^2))^1/3 * (3^2)^1/2 = 2^ 2/3 * 3 = 2^ 2 * 2^ 1/3  * 3 = 12 * 3^1/3
B) 64^1/6 - 64^1/2 = (2^6)^1/6 - (2^6)^1/2 = 2 - 8 = -6
C) 2 + 1/3 = 7/3
D) 1/2 + (2^4)^-1/2= 1/2 + 2^-2 = 1/2 + 1/4 = 3/4
E) 27 ^ 3/3 + 32 = 27 + 32 = 59
F) 25 ^ 3/2 - 8^ -2/3 = 5^ 3 - (2^(3*(-2)/3) = 125 - 1/4  = 124 + 3/4

3) A) log3 27 = 3, bo 3^3 = 27
B) log5 125 = 3
C) log3 3 = 1
D) log12 1 = 0, bo 12^0 = 1
E) log2 6 + log2 8 - log2 3 = log2 (6*8/3) = log2 16 = 4
F) log3 2 + log3 27 - log3 6 = log3 (2 /6) + 3 = log3 1/3 + 3 = -1 + 3= 2
G) log4 20 - log4 5 + log4 8 = log4 20/(5) * 8 = log4  32 = log2^2 16 * 2 = 
= log2^2 4^2 + log4 2 = log2 4 + log4 2 = 2+ 1/2 = 5/2