Proszę o pomoc z góry dziękuje

$(\frac{5}{6}+\frac{1}{3})/(2\frac{2}{3}1\frac{3}{4})=
(\frac{5}{6}+\frac{2}{6})/(\frac{32}{12}/)\frac{21}{12}=\frac{7}{1}*\frac{2}{11}=\frac{14}{11}=1\frac{3}{11}$

$\frac{3}{2}/[(\frac{1}{4}*\frac{3}{1})*\frac{5}{6}]=\frac{3}{2}/(\frac{3}{4}*\frac{5}{6})=\frac{1}{1}*\frac{12}{5}=\frac{12}{5}=2\frac{2}{5}$

$\frac{35}{8}/(\frac{13}{8}-\frac{3}{4})=\frac{35}{8}/(\frac{13}{8}-\frac{6}{8})=\frac{35}{8}*\frac{8}{7}=\frac{5}{1}*\frac{1}{1}=5$